One mole of an ideal gas $\left( {\frac{{{C_p}}}{{{C_v}}} = Y} \right)$ heated by law $P = \alpha V$ where $P$ is pressure of gas, $V$ is volume, $\alpha $ is a constant. What is the molar heat capacity of gas in the process
$C = \frac{R}{{\gamma - 1}}$
$C = \frac{{\gamma R}}{{\gamma - 1}}$
$C = \frac{R}{2}\frac{{\left( {\gamma - 1} \right)}}{{\left( {\gamma + 1} \right)}}$
$C = \frac{R}{2}\frac{{\left( {\gamma + 1} \right)}}{{\left( {\gamma - 1} \right)}}$
A cyclic process $ABCA$ is shown in $PT$ diagram. When presented on $PV$, it would be
The ratio of the specific heats $\frac{{{C_p}}}{{{C_V}}} = \gamma $ in terms of degrees of freedom $(n)$ is givln by
One mole of an ideal gas having initial volume $V$ , pressure $2P$ and temperature $T$ undergoes a cyclic process $ABCDA$ as shown below The net work done in the complete cycle is
$P-V$ plots for two gases during adiabatic process are shown in the figure. Plots $(1)$ and $(2)$ corresponds respectively to
In a Carnot engine, the temperature of reservoir is $927\ ^oC$ and that of sink is $27\ ^oC.$ If the work done by the engine is $12.6 \times 10^6 J,$ the quantitiy of heat absorbed by the engine from the reservoir is